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Brainliest Answer will be selected !!! |
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Answer» Solution A2=[2−3−41][2−3−41]A2=[2−3−41][2−3−41] A2=[16−9−1213]A2=[16−9−1213] 3A2+12A=[72−63−8451]3A2+12A=[72−63−8451] ADJ(3A2+12A)=[51638472]Adj(3A2+12A)=[51638472] |
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