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Bullets of 0.03 kg mass each, hit a plate at the rate of 200 bullet//s, with a velocity of 50 ms^(-1) and reflect back with a velocity of 30 ms^(-1). The average force acting onthe plate, in Newton is, |
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Answer» 120 `P_(1)=nmv_(1)= 200 xx 0.03 xx 50` ` = 300 kgms^(-1)` `P_(2)=-nmv_(2)= 200 xx 0.03 xx 30` ` = -180 kgms^(-1)` Force acting, `P_(2) – P_(1)=-180-300` |
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