By shifting origin to `(-1,2)` the equation `y^2+8x - 4y + 12 = 0` changes as `Y^2 = 4aX` then `a=`A. 1B. 2C. `-2`D. `-1`

By shifting origin to `(-1,2)` the equation `y^2+8x - 4y + 12 = 0` cha

1.	By shifting origin to `(-1,2)` the equation `y^2+8x - 4y + 12 = 0` changes as `Y^2 = 4aX` then `a=`A. 1B. 2C. `-2`D. `-1`
Answer» Correct Answer - B By shifting the origin at (1,2) we have `x=X+1,y=Y+2` Substituting these values in `y^(2)-8x-4y+12=0` we have `(Y+2)^(2)-8h(X+1)-4(Y+2)+12=0` `rArr Y^(2)-8X=0 rArr Y^(2)=8X`

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By shifting origin to `(-1,2)` the equation `y^2+8x - 4y + 12 = 0` changes as `Y^2 = 4aX` then `a=`A. 1B. 2C. `-2`D. `-1`

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