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    				| 1. | By what number should \(5^{-1}\) be multiplied so that the product many be equal to \((-7)^{-1}\)? | 
| Answer» Let the number \(5^{-1}\) should be multiplied by \(x\) According to the question: \(x\times 5^{-1}=(-7)^{-1}\) \(x\times \frac{1}{5}=\frac{1}{-7}\)[Using \(a^{-n}=\frac{1}{a^{n}}\)] \(x=\frac{1}{-7}\times \frac{5}{1}=\frac{5}{-7}\) Therefore \(5^{-1}\) should be multiplied by \(\frac{-5}{7}\) | |