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    				| 1. | By what number should \(5^{-1}\) be multiplied so that the product may be equal to \((-7)^{-1}\) ? | 
| Answer» Let the number should \(5^{-1}\) be multiplied by x According to the question: \(x\times 5^{-1}=(-7)^{-1}\) \(x\times \frac{1}{5}=\frac{1}{-7}\)[Using \(a^{-n}=\frac{1}{a^{n}}\)] \(x=\frac{1}{-7}\div \frac{5}{1}=\frac{5}{-7}\) \(x=\frac{1}{-7}\times \frac{5}{1}=\frac{5}{-7}\)= \(-\frac{5}{7}\)[Using and \(\frac{1}{a}\div \frac{1}{b}=\frac{1}{a}\times \frac{b}{1}\)] Therefore \(5^{-1}\) should be multiplied by \(\frac{-5}{7}\) | |