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By what percent the energy of the satellite has to be increased to shift it from an orbit of radius `r` to `(3r)/2`.A. `20%`B. `40%`C. 0.3333D. `66.66%` |
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Answer» Correct Answer - C B.E. of a satellite for an orbit of radius r is `E_(1)=(GMm)/(2r)` and for radius `(3r)/(2), E_(2)=(GMm)/(2xx(3)/(2)r)=(GMm)/(3r)` `therefore Delta E = (GMm)/(r )[(1)/(2)-(1)/(3)]=(GMm)/(6r)` `therefore` Percentage increase in energy `=(Delta E)/(E )=xx 100` `=((GMm)/(6r))/((GMm)/(2r))xx100` `= (1)/(3)xx100=33.33%` |
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