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By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature ? |
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Answer» <P>8·1% `rArrP_(2)=(P_(1)V_(1))/(V_(2))=(P_(1)V_(1))/((V_(1)-10/100V_(1)))` `rArrP_(2)=10/9P_(1)` % Increase in PRESSURE `=(P_(2)-P_(1))/(P_(1))xx100` `=(10/9P_(1)-P_(1))/(P_(1))xx100` `=100/9=11.1%` Thus correct choice is (d). |
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