1.

C-2.A stone of mass 5 kg is thrown upwards with a speed of 36 misec With what speed earth recoil Massof the earths 61024 kg (assuming that there is no external force on the system)

Answer» <p>M= mass of stone = 5 Kgv= velocity of stone = 36 m/sM= mass of Earth = 6*10²⁴ KgV= velocity of EarthApplying Law of Conservation of Momentum , mv + MV = 0V= -mv/M = -(5*36)/6*10²⁴ = -3 × 10^-23Here , - sign indicates that direction of velocity of Earth is opposite to that of stone</p>


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