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`C_(2)H_(4) +CI_(2) rarr C_(2)H_(4)CI_(2)` `DeltaH =- 270.6 kJ mol^(-1)K^(-1), DeltaS =- 139 J` a. Is the reaction favoured by entropy, enthalpy both or none? b. Find `DeltaG` if `T = 300K`. |
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Answer» a. Since `DeltaH =- ve`, exothermic process and is favoured, i.e., it will be spontaneous. b. `DeltaG = DeltaH - T DeltaS` `=- 270.6 xx 1000 - 300 xx (-139)` `=- 228900 J =- 228.9 kJ` |
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