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`C_(2)H_(4) +Cl_(2) rarr C_(2)H_(4)Cl_(2) , Delta H = - 270.6 kJ mol^(-1), Delta S = - 139.0 J K^(-1) mol^(-1)` (i) Is the reaction favoured by entropy , enthalpy, both or none ? (ii) Find `Delta G` if `T = 300 K`. |
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Answer» (i) As `Delta H` is `-` ve , reaction isfavoured by enthalpy. As ` Delta S` is -ve, it is not favoured by entropy. (ii) `Delta G =Delta H - T DeltaS` `= - 270.6 k J mol^(-1) - 300 K ( -139 xx 10^(-3) kJ K^(-1) mol^(-1))` `= -270.6 + 41.7 kJ mol^(-1)` `= - 228.9kJ mol^(-1)` |
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