1.

`C_(2)H_(6)(g) + 3.5O_(2)(g) rarr 2CO_(2)(g) + 3H_(2)O(g)``DeltaS_("vap") (H_(2)O,l) = "x"_(1)calK^(-1)` (boiling point `=T_(1)`) `DeltaH_(f)(H_(2)O,l) = "x"_(2)` `DeltaH_(f)(CO_(2)) = "x"_(3)` `DeltaH_(f)(C_(2)H_(6)) = "x"_(4)` Hence , `DeltaH` for the reaction is-A. `2"x"_(3) + 3"x"_(2)-"x"_(4)`B. `2"x"_(3) + 3"x"_(2)-"x"_(4) + 3"x"_(1)T_(1)`C. `2"x"_(3) + 3"x"_(2)-"x"_(4) - 3"x"_(1)T_(1)`D. `"x"_(1)T_(1) + "X"_(2) + "X"_(3) - "x"_(4)`

Answer» Correct Answer - B
`H_(2)O(I) rarr H_(2)O(g) DeltaH_("vap") = DeltaS_("vap") T_(B.P) = "x"_(1)T_(1)`
`DeltaH_(f)(H_(2)O,g) = DeltaH_(f)(H_(2)O,I) + DeltaH_("vap") = "x"_(2) + "x"_(1)"T"_(1)`
`DeltaH_("reaction") = 2DeltaH_(f) (CO_(2),g) + 3DeltaH_(f)(H_(2)O,g) - DeltaH_(f)(C_(2)H_(6),g)`
`" "=2"x"_(3) + 3("x"_(2) + "x"_(1)"T"_(1)) - "x"_(4)=2"x"_(3) + 3"x"_(2) + 3"x"_(1)"T"_(1) - "x"_(4).`


Discussion

No Comment Found

Related InterviewSolutions