1.

c) State ionic radius19 a ) A carbon compound contains l 2.8% carbon, 2.1% hydrogen, 85.1% bromine. The molecularmass of the compound is 188. Calculate the molecular formula.3+2)

Answer»

C=12.8% at.wt. of C=12H=2.1%. at.wt. of H=1Be=85.1%. at.wt. of Br=80Now, 12.8/12 =1.067 2.1/1 = 2.1 85.1/80=1.067

Dividing with 1.067 to get simple atomic ratio,

1.067/1.067=12.1/1.067=21.067/1.067=1E.F= CH2BrE.F

weight=12+(2×1)+80=94

Molecular weight=187.9 (given)

n=187.9/94= 2M.F= (E.F)×2 =(CH2Br)×2 =C2H4Br2

so, the answer of this question❓❓❓ is (C2HBr2



Discussion

No Comment Found

Related InterviewSolutions