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CaCl is colourless, while CuSO_(4).5H_(2)O is coloured. Explain? |
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Answer» Solution :Electronic configuration of `Cu^+` ion is [Ar] `4s^0 3d^9` In `CUCL, Cu^(+)` ion has no unpaired d- electron . THUS d-d transition is no POSSIBLE in CuCl and HENCE it is colourless. In `CuSO_4. 5H_2O` the `Cu^(2+)` ion has one unpaired d-electron in 3d -subshell . Thus, d-d transition is possible and hence it EXHIBITS colour. |
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