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Caculate the mass of `1cm^(3)`of oxygen kept at STP. |
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Answer» `n=(PV)/(RT)= (1 xx 1 xx 10^-3)/( 0.082 xx 273 )= 10^-3/22.4` ` mass= ((10^-3 xx 32)g)/224 ` ` = 1.428 xx 10^-3 g ` ` =1.428 mg ` |
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