calcualate the amount of heat evolved when `500 cm^(3)` of 0.1M HCl is mixed with `200 cm^(3)` of 0.2 M NaOH.A. 57.3 kJB. 2.865 kJC. 2.292 kJD. 0.573 kJ

calcualate the amount of heat evolved when `500 cm^(3)` of 0.1M HCl is

1.	calcualate the amount of heat evolved when `500 cm^(3)` of 0.1M HCl is mixed with `200 cm^(3)` of 0.2 M NaOH.A. 57.3 kJB. 2.865 kJC. 2.292 kJD. 0.573 kJ
Answer» Correct Answer - c `HCl+NaOHto NaCl+H_(2)O` at t=0, number of moles = `(500xx0.1)/1000 = (200xx0.2)/1000 ` =0.05 =0.04 during neutralisation of 1 mole of NaOH by 1 mole of HCl, heat ecolved = 57. 3 kJ to neutralised 0.04 moles of NaOH by 0.04 molw of NaOH, heat evolved `57.3 xx 0.04` = 2.292 kJ

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calcualate the amount of heat evolved when `500 cm^(3)` of 0.1M HCl is mixed with `200 cm^(3)` of 0.2 M NaOH.A. 57.3 kJB. 2.865 kJC. 2.292 kJD. 0.573 kJ

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