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Calcualte the maximum efficiency of an engine operating between`110^(@)C`and`25^(@)C`.A. `11.1%`B. `22.2%`C. `33.3%`D. `44.4%` |
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Answer» Correct Answer - B Maximum efficiency of an engine working between temperature `T_(2)` and `T_(1)` is given by `eta=(T_(2)-T_(1))/(T_(2))=(383.293)/(383)=0.222eta=22.2%` |
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