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Calculate (a) the wavelength and (b) the frequencey of the `Hbeta` line of the Balmer series for hydrogen. |
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Answer» a. `H_(beta)` line of Balmer series corrresponds to the transition from `n = 4` to `n = 2`level . The corrresponds wavelength for `H_(beta)` line is ` (1)/(lambda) = (1.097 xx 10^(7)) [(1)/(2^(2)) - (1)/(4^(2))]` `= 0.2056 xx 10^(7) m` `lambda = 4.9 xx 10^(-7)) m` ltrbgt b. `f = (c )/(lambda) = (3.0 xx 10^(8))/(4.9 xx 10^(-7))` `= 6.12 xx 10^(14) Hz` |
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