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Calculate and compare the energy released by (a) fusion of 1.0 kg of hydrogen deep within Sun and (b) the fission of 1.0 kg of " "^(235)U in a fission reactor. |
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Answer» Solution :(a) Fusion REACTION is `" "_(1)^(1)H +" "_(1)^(1)H+" "_(1)^(1)H+" "_(1)^(1)H to " "_(2)^(4)He + 2+" "_(1)^(0)e + 2nu+ 26 MeV` `therefore` The energy released by 1 kg of hydrogen` = (6.023xx10^(23)xx26)/(4xx10^(-3))MeV =3.9 X 10^(27) MeV` (b) The energy released in one act of fission of `" "^(235)U` is = 200 MeV `therefore` Energy released in fission of 1 kg of `" "_(92)^(235)U= (6.023 xx 10^(23)xx200)/(235xx10^(-3)) MeV =5.1 xx 10^(26) MeV` `therefore ("Energy released in fusion of 1 kg of hydrogen")/("Energy released in fission of 1 kg of" " "^(235)U)=(3.9xx 10^(27))/(5.1xx10^(26)) =7.65 APPROX 8` |
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