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Calculate d^2i(0)/dt^2 from the given circuit.(a) 10^-6A/s^2(b) 10^-3A/s^2(c) 10^6A/s^2(d) 10^3A/s^2I have been asked this question in an interview for job.Origin of the question is Transients in CR Networks in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct answer is (b) 10^-3A/s^2

The BEST EXPLANATION: APPLYING KVL to the given circuit, we get:

100+10i(0)+1/10*integral(i(0)dt)=0

Differentiating once, we get:

10di(0)/dt+1/10*i.

Differentiating once again, we get:

10d^2i(0)/dt^2+10di(0)/dt=0.

Substituting the values of di/dt from the previous explanation, we get d^2i(0)/dt^2=10^-3A/s^2.


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