1.

Calculate de Broglie wavelength of neutrons whose energy iseV.(Given mass of electrons (1.67 xx 10^(-27)kg)

Answer»

SOLUTION :We know that `lambda = h/SQRT(2ME) = (6.6 XX 10^-34)/sqrt(2 xx 1.67 xx 10^-27 xx 1.6 xx 10 ^-10`
= `0.2857 xx 10^-10 = 0.2857 A^@`


Discussion

No Comment Found

Related InterviewSolutions