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Calculate de Broglie wavelength of neutrons whose energy iseV.(Given mass of electrons (1.67 xx 10^(-27)kg) |
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Answer» SOLUTION :We know that `lambda = h/SQRT(2ME) = (6.6 XX 10^-34)/sqrt(2 xx 1.67 xx 10^-27 xx 1.6 xx 10 ^-10` = `0.2857 xx 10^-10 = 0.2857 A^@` |
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