InterviewSolution
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InterviewSolution
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Calculate `Delta U` reaction for the hydrogenation of acetalence at constant volume and at `77^(@)C`. Given that `-DeltaH_(f)(H_(2)O)= -678` kcal mole , `Delta H_("comb")(C_(2)H_(2))= -310.1 kcal//ms^(2)` |
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Answer» Correct Answer - 40 Required equation is : `C_(2)H_(2(g)) + H_(2(g)) rarr C_(2)H_(4(g)) " "DeltaH-DeltaU-=?` `H_(2(g))+ (1)/(2)O_(2(g)) rarr H_(2)O(l) " " DeltaH- = -67.8 " ""…"`(1) `C_(2)H_(2(g)) + (5)/(2)O_(2(g)) rarr 2CO_(2) + 2H_(2)O(l)" " DeltaH-=-310.1" ""..."`(2) `C_(2)H_(4) + 3O_(2(g)) rarr 2CO_(2(g)) + 2H_(2)O(l)" " DeltaH-=-337.2 " ""..."(3)` `(1) + (2) -(3)` `implies C_(2)H_(2(g)) rarr C_(2)H_(4(g))` `DeltaH_(rxxn) = -67.8 - 310.1 + 337.2 = -40.7 KCal` `DeltaH = DeltaU + Deltan(g)RT` `-40.7= DeltaU +(-1) xx 2 10^(-3) xx 350` `DeltaU= -40.7+.7` `DeltaU=-40"KCal"//"mole"` |
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