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Calculate `DeltaG^(@)` (kJ/mol) at `127^(@)C` for a reaction with `K_("equilibrium")=10^(5)` :A. `-38.294`B. `-16.628`C. `-9.16`D. None of these |
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Answer» Correct Answer - A `DeltaG^(@)=-RTlnK=-8.314xx10^(-3)xx400ln10^(5)` `DeltaG^(@)=-38.294 " kJ"` |
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