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Calculate `DeltaG_(reaction) ("kJ"//"mol")` for the given reaction at 300 K `A_(2)(g)+B_(2)(g)hArr2Ab(g)` and at particle pressure of `10^(-2)`bar and `10^(-4)` Given : `Delta H_(f)^(@) AB =180 kJ//mol," "DeltaH_(f)^(@) A_(2)=60 kJ//mol` `Delta H_(f)^(@) B_(2) = 29.5 kJ//mol," "DeltaS_(f)^(@) AB=210 J//K-mol` `Delta S_(f)^(@) A_(2) = 190 kJ//mol," "DeltaS_(f)^(@) B_(2)=205 J//K-mol` Use :` 2.303 Rxx300=5750 "J"//"mole" ` |
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Answer» Correct Answer - 234 |
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