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Calculate `DeltaH` at `85^(@)C` for the reaction: `Fe_(2)O_(3)(s) +3H_(2)(g) rarr 2Fe(s) +3H_(2)O(l)` The data: `DeltaH_(298)^(Theta) =- 33.0 kJ mol^(-1)` and `{:("Substance",Fe_(2)O_(3)(s),Fe(s),H_(2)O(l),H_(2)(g)),(C_(P)^(@)(JK^(-1)mol),103.0,25.0,75.0,28.0):}` |
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Answer» `Fe_(2)O_(3)(s)+3H_(2)to2Fe+3H_(2)O` `DeltaC_(P)=(C_(P))_(P)-(C_(P))_(R)` `=(2xx25.1+3xx75.3)-(103.8+3xx28.8)` `=276.1-190.2=85.9J` `(DeltaH_(T_(2))-DeltaH_(T_(1)))/(T_(2)-T_(1))=DeltaC_(P)` `(DeltaH_(358)-(-33.29))/(358-298)=85.9xx10^(-3)` `DeltaH_(358)=-28.14kJ//mol` |
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