1.

Calculate `DeltaH_(f)^(@)` for chloride ion from the following data `:` `(1)/(2)H_(2(g))+(1)/(2)Cl_(2(g))rarr HCl_((g)),DeltaH_(f)^(@)=-92.4kJ` `HCl_((g))+nH_(2)O rarr H_((aq.))^(+)+Cl_((aq.))^(-),DeltaH^(@)=-74.8kJ` `DeltaH_(f)^(@) H_((aq.))^(+)=0.0kJ`

Answer» Given,
`(1)/(2)H_(2(g))+aq. rarr H_((aq.))^(+)+E, DeltaH^(@)=0 ....(1)`
`(1)/(2)H_(2(g))+(1)/(2)Cl_(2(g))rarr HCl_((g)), DeltaH^(@)=-92.4kJ ....(2)`
`CHl_((g))+nH_(2)O_((l)) rarr H_((aq.))^(+)+Cl_((aq.))^(-), DeltaH^(@)=-74.8kJ ...(3)`
Add `eq. (2)` and `(3)`
`(1)/(2) H_(2(g))+(1)/(2)Cl_(2(g))+nH_(2)Orarr H_((aq.))^(+)+Cl_((aq.))^(-), DeltaH^(@)=-167.2kJ ....(4)`
Subtract `eq. (2)` from `(4)`
`ul({:((1)/(2)H_(2(g)),+aq.,rarr,H_((aq.))^(+),+e,,DeltaH^(@)=0),(-,-,,-,-,-):})`
`:. e+(1)/(2)Cl_(2(g))+aq. rarr Cl_((aq.))^(-), DeltaH=-167.2kJ`
Heat of formation for `Cl_((aq.))^(-)=-167.2kJ`


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