InterviewSolution
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InterviewSolution
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Calculate `Deltah` for the eaction `BaCO_(3)(s)+2HCI(aq) rarr BaCI_(2)(aq)+CO_(2)(g)+H_(2)O(l)` `Delta_(f)H^(Theta) (BaCO_(3)) =- 290.8 kcal mol^(-1), Delta_(f)H^(Theta) (H^(o+)) =0` `Delta_(f)H^(Theta) (Ba^(++)) = - 128.67 kcal mol^(-1)`, `Delta_(f)H^(Theta)(CO_(2)) =- 94.05 kcal mol^(-1)`, `Delta_(f)H^(Theta) (H_(2)O) =- 68.32 kcal mol^(-1)` |
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Answer» `{:(underset(darr)BaCO_(3)(s)+2H^(o+)+2CI^(Theta)),(Ba^(2)+2CI^(Theta)+CO_(2)+H_(2)O):}` `DeltaH = (Delta_(f)H^(Theta)Ba^(2+) +Delta_(f)H^(Theta)CO_(2)+H_(2)O)-(Delta_(f)H^(Theta)BaCO_(3) +Delta_(f)H^(Theta)H^(o+))` `=(-128.67 - 94.05 -68.32) -[-290.8 xx2xx0)` `=-- 0.24 kcal` |
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