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Calculate `DeltaH` of the reaction, `H-underset(CI)underset(|)overset(H)overset(|)C-CI(g)rarrC(s) +2H(g) +2CI(g)` Bond enegry for `C-H` bond and `C-CI` bond are `400 kJ` and `320kJ`, respectively. |
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Answer» `DeltaH^(Theta) =` Sum of bond energies of reactants -Sum of bond energies of products `=[2 xx (C -H) +2 xx (C -C1)] = 0` [All the prodcuts are free atoms] `= 2xx 400 + 2xx 320` `= 800 + 640 = 1440kJ` |
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