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InterviewSolution
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Calculate electronegativity of carbon at Pauling scale Given that : ` E_(H-H) =104 .2 kcal "mol"^(-1) E_(C-C) =83.1 kcal "mol"^(-1)` , `E_(C-H) =98.8 kcal "mol"^(-1)`. Electronegativity of hydrogen `=2.1`. |
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Answer» According to Pauling eqwuation , ` X_C -X-H =0. 208[E_(C-H)-(E_(H-H) xxE_(C-C))^(1//2)]^(1//2)` Where ` X_C` and ` X_H` are electronegativity of `C ` and `H` respectively . ` X_C-2.1 =0.208 [98.8 -(104.2 xx83.1)^(1//2)]^(1//2) 83.1)^(1//2)]^(1//2)` ` X-C -2.1 =0.498 ` or `X_C =2.598`. |
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