1.

Calculate emf of the cell:Zn(s)|Zn2+(aq)||Fe2+(aq)|Fe(s) if Zn2+ = -0.76v EFe2+ = -0.44v

Answer»

Zn(s)|Zn2+(aq)||Fe2+(aq)|Fe(s);

cell = -0.44 - (-0.76)

 = 0.32V



Discussion

No Comment Found