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Calculate emf of the cell:Zn(s)|Zn2+(aq)||Fe2+(aq)|Fe(s) if Zn2+ = -0.76v EFe2+ = -0.44v |
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Answer» Zn(s)|Zn2+(aq)||Fe2+(aq)|Fe(s); E°cell = -0.44 - (-0.76) = 0.32V |
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