1.

Calculate energy of photon having 6840 Å wavelength (hc=12400 eVÅ)

Answer»

1.81 EV
3.6 eV
`-13.6 eV`
12.1 eV

Solution :`lambda=6840 Å`
`THEREFORE f=(c )/(lambda) f=( c)/(lambda)implieshf=(hc)/(lambda),hc=12400 eVÅ`
ENERGY of PHOTON =`(12400 eVÅ)/(6840Å)=1.81 eV`


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