Calculate enthalpy change of the following reaction `:` `H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g))` The bond energy of `C-H,C-C,C=C,H-H` are `414,347,615` and `435k J mol^(-1)` respectively.

Calculate enthalpy change of the following reaction `:` `H_(2)C=CH_(2(

1.	Calculate enthalpy change of the following reaction `:` `H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g))` The bond energy of `C-H,C-C,C=C,H-H` are `414,347,615` and `435k J mol^(-1)` respectively.
Answer» `DeltaH_(Reaction)=` Bond energy data for the formation of bond `+` Bond energy data for the dissociation of bond `=-[1-(C-C)+6(C-H)]+[1-(C=C)+4(C-H)+1-H-H)]` `=-1(C-C)-2(C-H)+1(C=C)+1(H-H)` `=-347-2xx414+615+435=-125kJ`

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Calculate enthalpy change of the following reaction `:` `H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g))` The bond energy of `C-H,C-C,C=C,H-H` are `414,347,615` and `435k J mol^(-1)` respectively.

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