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InterviewSolution
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Calculate `gamma` of a gaseous mixture consisting of 3 moles of nitrogen and 2 moles of carbon dioxide. |
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Answer» The `gamma` of a mixture is given by `(n_(1) + n_(2))/(gamma -1) = (n_(1))/(gamma_(1) - 1) + (n_(2))/(gamma_(2) - 1)` Here `n_(1) = 3, n_(2) = 3, gamma_(1) = 7//5` (as nitrogen is diatomic and `gamma_(2) = 4//3` (as carbon dioxide is triatomic) Therefore, `(5)/(gamma -1) = (3)/((7)/(5) - 1) + (2)/((4)/(3) - 1) implies gamma = 1.37` |
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