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Calculate `[H^(+)]` in a `0.20M` solution of dichloriacetic acid `(K_(a)=5xx10^(-2))` that also contains `0.1M` sodium dichloroacetate.Neglect hydrolysis of sodium salt. |
Answer» `{:(,CHCl_(2)COOHhArr,CHCl_(2)COO^(-),+,H^(+)),("Before diassociation",0.2,-,,-),("After dissociation",(0.2-x),x,,x),(,CHCl_(2)COONararr,CHCl_(2)COO^(-),+,Na^(+)),(,,0.1,,0.1):}` for the dissociation of acid `K_(a)=5xx10^(-2)=([CHCl_(2)COOH^(-)][H^(+)])/([CHCH_(2)COOH])or 0.05=([0.1+x][x])/([0.2-x])` `x=0.05` or `[H^(+)]=0.05M` |
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