InterviewSolution
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InterviewSolution
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Calculate `K_(c)` for the reaction: `2H_(2)(g)+S_(2)(g) hArr 2H_(2)S(g)` if `1.58` mol `H_(2)S, 1.27` mol `H_(2)` and `2.78xx10^(-6)` mol of `S_(2)` are in equilibrium in a flask of capacity `180 L` at `750^(@)C`. |
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Answer» Correct Answer - A::B::C `{:(,2H_(2)(g),+,S_(2)(g),hArr,2H_(2)S(g)),("moles at",1.27,,2.78xx10^(-6),,1.58),("equilibrium",,,,,):}` Volume of container `=180 L` `:. K_(C)=([H_(2)S]^(2))/([H_(2)]^(2)[S_(2)])=((1.58/180)^(2))/((1.27/180)^(2)((2.78xx10^(-6))/180))` `=((1.58)^(2)xx180)/((1.27)^(2)xx(2.78xx10^(-6)))` `K_(C)=1.002xx10^(8)L "mol"^(-1)` |
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