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Calculate `K_(c )` for the reaction `KI + I_(2) hArr KI_(3)`. Given that initial weight of `KI` is `1.326 g` weight of `KI_(3)` is `0.105 g` and number of moles of free `I_(2)` is `0.0025` at equilibrium the volume of solution is `1-L`.A. `0.032`B. `0.024`C. `0.064`D. 0.012 |
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Answer» Correct Answer - A |
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