1.

Calculate `K_(p)` for the following reaction if partial pressures of `NH_(3), N_(2) and H_(2)` are 0.4,0.3,0.2, atm, respectively. `2NH_(3) hArr N_(2)+3H_(2)`

Answer» `K_(p)=(p^(3)H_(2).pH_(2))/(P^(2)NH_(2))`
`K_(p)=((0.2)^(3)*(0.3)("atm")^(4))/((0.4)^(2)("atm")^(2))`
`K_(p)=0.015 "atm"^(2)`


Discussion

No Comment Found

Related InterviewSolutions