1.

Calculate LC for a full wave rectifier which provides 10V dc at 100mA with a maximum ripple of 2%. Input ac frequency is 50Hz.(a) 40*10^-6(b) 10*10^-6(c) 30*10^-6(d) 90*10^-6I got this question in an interview for job.I'm obligated to ask this question of L-Section Filter topic in chapter Application of Diodes of Electronic Devices & Circuits

Answer»

The correct CHOICE is (a) 40*10^-6

To EXPLAIN: LC=1/6√2ω^2ϒ

ω=2πf=314

By putting the values, LC=1/6√2(314)^2 0.02=40*10^-6.



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