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Calculate molecular diameter for a gas if its molar exclued volume is `3.2 pi ml`. (in nenometer) (Take `N_(A) = 6.0 xx 10^(23))` |
Answer» Correct Answer - 2 `4N(4)/(3)pir^(3) = 3.2 xx pi xx 10^(-3)` `4 xx 6 xx 10^(23) xx (4)/(3) pir^(3) = 3.2 pir^(3) = 3.2 pi xx 10^(-3)` `r^(3) = 10^(-9)m` `r = 1 nm` ltbr. `d = 2r = 2nm` |
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