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Calculate moment of inertia of a circular disc about a transverse axis through the centre of the disc. Given, diameter of disc is `40 cm`, thickness `= 7 cm` and density of material of disc `= 9 g cm^(-3)`. |
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Answer» Here, `R = 40//2 = 20cm, x = 7 cm, rho = 9 g cm^(-3)` Mass of disc, `M = piR^(2).x.rho` `=(22)/(7) (20)^(2) xx 7 xx 9 = 7.92 xx 10^(4) g` `I = (1)/(2)MR^(2) = (1)/(2) xx 7.92 xx 10^(4) (20)^(2)` `= 1.584 xx 10^(7) g cm^(2)` |
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