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Calculate normality of 2.1% (w/V) H2SO4 solution?(1) 2.14 N(2) 4.28 N(3) 0.428 N(4) 0.214 N |
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Answer» 21% w/v H2SO4 means 21 g of H2SO4 is present in 100 ml of solution. No. of equivalents of H2SO4 = weight / Gram equivalent of H2SO4= (21 / 49) moles Normality = (Equivalents × 1000) / Volume of solution= [(21 / 49) × 1000] / 100= 4.28 N Not 21% but ok i have understood.Thanks. |
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