InterviewSolution
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InterviewSolution
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Calculate the (a)momentum and (b) de - Brogile wavelength of the electrons accelerated through a potential difference of 56 V. |
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Answer» Mass of the electron , m = `9 xx 10^(-31) " kg , "` Potential difference , V - 56 V Momentum of electrons , mv = ` sqrt ( 2 e V m ) = sqrt(2 xx (1.6 xx 10^(-19) )xx56 xx 9 xx 10^(-31))= 4.02 xx 10^(-24) " kg ms"^(-1)` (b) de - Broglie wavelength , ` lambda = h/p = h/(m v)= (6.62 xx 10^(-34))/(4.04 xx 10^(-24))= 1.64 xx 10^(-10) m ` |
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