Saved Bookmarks
| 1. |
Calculate the (a) Momentum, and (b) De-broglie wavelength of the electrons accelerated through a potential difference of 56 V. |
|
Answer» <P> SOLUTION :Here accelerating potential difference `V=56V`(a) `THEREFORE` Momentum of electron `p=SQRT(2mK)=sqrt(2mVe)=sqrt(2xx9.11xx10^(-31)xx56xx1.6xx10^(-19))` `=4.04xx10^(-24)KG" ms"^(-1)` (b) `therefore`de-Broglie wavelength `lamda=(h)/(p)=(6.63xx10^(-34))/(4.04xx10^(-24))=1.64xx10^(-10)m=0.164nm`. |
|