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Calculate the amount of work done, in joules, when 2.5 mole of H2O vaporizes at 1.0 atm and 25°C. Assume the volume of liquid H2O is negligible compared to that of vapor. (1 L·atm = 101.3 J) (A) 6,190 kJ (B) 6.19 kJ (C) 61.1 J (D) 5.66 kJ (E) 518 J |
Answer» The Correct option is (B) 6.19 kJ |
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