1.

Calculate the standard enthalpy change for the reaction2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l). Given: 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH° = –11,020 kJ/mol2CO(g) + O2(g) → 2CO2(g) ΔH° = –566.0 kJ/mol(A) 1.0454 x 104 kJ/mol(B) –8,756 kJ/mol(C) 1.1586 x 104 kJ/mol(D) –6,492 kJ/mol (E) –1.0454 ´ 104 kJ/mol

Answer»

(B) –8,756 kJ/mol



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