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Calculate the area of cross section of the multi plate capacitor having C=20F, actual permittivity=5F/m n=3 and d=2m.(a) 1m^2(b) 2m^2(c) 3m^2(d) 4m^2The question was posed to me during a job interview.My query is from Capacitance of a Multi Plate Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer» RIGHT answer is (d) 4m^2

Easiest explanation: The formula for capacitance of a multi plate capacitor: C=Actual PERMITTIVITY*(n-1)*A/d.

Substituting the given VALUES in the EQUATION, we GET A=4m^2.


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