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Calculate the average energy required to extract a nucleon from the nucleus of an alpha- particle ,proton and neutron are 4.00150 a.m.u 1.00728 a.m.u and 1.00867 amu respectively . |
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Answer» Solution :Mass defect, `(DELTAM)=2(m_p+m_n)-m_N` =4.0319-4.00150=0.0304 amu BINDING energy of `ALPHA`-particle = `Deltamxx931.5` MeV =0.034 x 931.5 = 28.3 MeV Average energy required to extract nucleon `=28.3/4` = 7.07 MeV |
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