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Calculate the binding energy and binding energy per nucleon (in MeV) of a nitrogen nucleus (""_(7)^(14)N)from the following data: Mass of proton=1.0078 u Mass of neutron=1.00867 u Mass of nitrogen nucleus=14.00307 u |
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Answer» <P> Solution :Calculation of mass defect.`Delta m=Zm_(p)+(A-Z)m_(n)=-M` `Delta =7xx1.00783+7xx1.00876-14.00307` Calculation of binding energy for 1 U(1amu) binding energy `Delta=931.5` MEV For `0.11243u`, Ginding energy `DeltaE=0.11243xx931x931.5 MeV` `=104.72854 MeV` Binding energy per nucloen `=(BE)/(A)=(104.7258)/(14)` `=7.4861.` MeV/ nucloeon |
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