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Calculate the binding energy of a K electron in vanidium whose L absorption edgerhas the wavelength lambda_(L)=2.4nm. |
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Answer» Solution :From the diagram above we see that the binding energy `E_(B)` of a `K` electron is the sum of the energy of a `K_(alpha)` line and the energy corresponding to the `L` edge of absorption spectrum `E_(b)=(2pi ħc)/(lambda_(L))+(3)/(4)ħR(Ƶ1)^(2)` For vanndium `Ƶ=23` and the energy of `K_(alpha)` line of vanadium has been CALCULATED in problem 134(b). Using `(2 pi ħc)/(lambda_(L))= 0.51 keV` for `lambda_(L)=2.4nm` we get `E_(b)=5.46keV` |
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