Calculate the binding energy of a `K` electron in vanidium whose `L` absorption edgerhas the wavelength `lambda_(L)=2.4nm`.

Calculate the binding energy of a `K` electron in vanidium whose `L` a

1.	Calculate the binding energy of a `K` electron in vanidium whose `L` absorption edgerhas the wavelength `lambda_(L)=2.4nm`.
Answer» From the diagram above we see that the binding energy `E_(b)` of a `K` electron is the sum of the energy of a `K_(alpha)` line and the energy corresponding to the `L` edge of absorption spectrum `E_(b)=(2pi ħc)/(lambda_(L))+(3)/(4)ħR(Ƶ1)^(2)` For vanndium `Ƶ=23` and the energy of `K_(alpha)` line of vanadium has been calculated in problem 134(b). Using `(2 pi ħc)/(lambda_(L))= 0.51 keV` for `lambda_(L)=2.4nm` we get `E_(b)=5.46keV`

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Calculate the binding energy of a `K` electron in vanidium whose `L` absorption edgerhas the wavelength `lambda_(L)=2.4nm`.

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