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Calculate the binding Energy of an alpha (alpha) particle in Mev from the following data. Mass of Hlium Nucleus = 4.00260u Mass of neutron= 1.008662u Mass of proton = 1.007825u |
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Answer» Solution :Alpha particle: `""_(2)^(4)He` Z=2 and A=4 Mass DEFECT: `Delta m= [Zm_(P) + (A -Z)m_(N)]-M` `Delta m= 2 XX 1.007825 + 2 xx 1.008662- 4.00260` `Delta m= 2.01565 + 2.017324-4.00260` `Delta m= 0.030374u` Binding energy : `E_(b)= Delta m xx 931 MeV= 0.030374 xx 931` MeV `E_(b)= 28.2782` MeV |
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